(x^2-2x+3)=(x^2-3)

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Solution for (x^2-2x+3)=(x^2-3) equation: 



(x^2-2x+3)=(x^2-3)

We move all terms to the left:

(x^2-2x+3)-((x^2-3))=0

We get rid of parentheses

x^2-2x-((x^2-3))+3=0



We calculate terms in parentheses: -((x^2-3)), so:

(x^2-3)

We get rid of parentheses

x^2-3

Back to the equation:

-(x^2-3)



We get rid of parentheses

x^2-x^2-2x+3+3=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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